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Longitudinal Force on Bearings

 
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Hisham
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Joined: 27 Sep 2015
Posts: 5

PostPosted: Thu Oct 12, 2017 10:08 am    Post subject: Longitudinal Force on Bearings Reply with quote

Hi All,

Acc. to IRC 6 2017, Cl 211.5.1.1, the horizontal force at the bearing level is calculated as the greater of two expressions.
I don't understand how the second expression is formulated for a fixed bearing... Fh/2 + u * (Rg + Rq).

Could someone help me understand the same.

Thanks and Regards,
Hisham
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kunalkansara
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Joined: 26 Jan 2003
Posts: 185

PostPosted: Tue Oct 17, 2017 5:23 pm    Post subject: Reply with quote

Dear Er Hisham

The second equation allows for the possibility when the friction at the free-to-slide end is significant or the applied longitudinal force is small compared to the friction force potential of the free-to-slide end (signified by if the friction force is greater than half of the applied longitudinal force). In such cases the distribution of the applied longitudinal is half-half for the fixed and free end.

I don't have the latest version of the IRC:6, but if you go on to read other design scenarios such as at two ends of a SS single span with no bearings, or with identical elastomeric at both ends, you will be able to appreciate this more easily. In fact, the equations for the design scenario with continuous supports cover both scenarios i.e. if friction is significant or not significant compared to the applied longitudinal forces.

Hope this helps.

Thanks
Kunal
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